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1、1. [log4(3) + log8(3)]×[log3(2) + log9(2)] = [(1/2)·log2(3) + (1/3)·log2(3)]·[log3(2) +(1/2)· log3(2)] = (5/6)·log2(3)·(3/2)log3(2) = [(5/6)·(3/2)]·[log2(3)·log3(2)] = (5/4)·(1) = 5/4 2. log2(3)× [log3(4) + log9(2)] = log2(3)·[2·log3(2) + (1/3)·log3(2)] = log2(3)·[(7/3)·log3(2)] = (7/3)[log2(3)·log3(2)] = 7/3 3.请输入正确的格式。

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